Posted on October 10, 2010.
Infrared LEDa I have 2 100 ohm resistors, 2 infrared LEDs, and a 9 volt battery. I want to make a flashlight for my infrared night vision. How can I make this work. I am a total noob so forgive me if the only thing I know is what is positive leads.
Not sure how much "vision" that will give you 2 LED, maybe just a few centimeters (dimmed inverse square of distance).
A night vision 40ft sports security cameras at least 30 LEDs.
And you know that your eyes can not see infrared, you need a thermal imaging camera or other instrument for making night vision ....
The circuit is quite easy: Connect one end of the two resistors to "most" of the battery. The other ends of resistors with each round "most" of the LED. Connect the two "less-es" of the LED for "less" of the battery.
Make sure the LEDs are "high power" types (direct current = 100 mA) depending on your resistance (100 Ohm) and resulting current (90mA).
What he said. In addition, a digital camera with a screen will be useful in testing the intensity of the LED, even if you can not see the light, the camera.